How many grams of 12 (molecular iodine) will be required to completely react with 35.20 ml of 0.150 M Na₂S₂O3 solution according to the balanced
equation below?
12 (s) + 2 Na₂S₂O₂ (aq) → Na₂S4O6 (aq) + 2 Nal (aq)

A.O 1.34 g of 1₂
B.0.335 g of 1₂
C.0.670 g of 12
D.0.751 g of 1₂