How would you write the following expression as a sum or difference?
log ( 3^squared 2-x/3x)

a. 1/3 log (2-x) + log 3x)
b. 1/3 log (2 - x) - log 3x
c. 1/3 log (2-x) - log x
d. 1/3 log (2 - x) + log 3x