Bladen5294 Bladen5294

13-03-2024
Mathematics

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Compute y' for y=(tan(x) ) ˣ²+1)
a) y'=(tan(x) ) ˣ²+1) (2x tan(x) +(x²+1) sec²(x) /tan(x) )
b) y'=(tan(x) ) ˣ²+1) (2x ln(tan(x) ) +(x²+1) sec²(x) /tan(x) )
c) y'=(tan(x) ) ˣ²+1) (2x tan(x) +(x²+1) sec²(x) )
d) None of the other answers

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