If the area is 72 and the perimeter is 34, what are it's dimensions

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11-05-2018
Mathematics

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If the area is 72 and the perimeter is 34, what are it's dimensions

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Аноним Аноним · Answer 1 · 2018-05-11T12:54:00+02:00

Аноним Аноним

11-05-2018

xy = 72
2x + 2y = 34 (Im assuming uts a rectangle or square)

2 (72/y) + 2y = 34
144 + 2y^2 = 34y
2y^2 - 34y + 144 = 0
y = 9 or 8

So the length is 9 and width = 8

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