Respuesta :

gmany
[tex]Use:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\n\log_ab=\log_ab^n\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\a^{-n}=\dfrac{1}{a^n}[/tex]

[tex]3\log_5\dfrac{w^2}{w^3}=3\log_5w^{2-3}=3\log_5w^{-1}\\\\=\log_5\left(w^{-1}\right)^3=\log_5w^{-1\cdot3}=\log_5w^{-3}=\log_5\dfrac{1}{w^3}[/tex]

Answer: D

Step-by-step explanation:

I had to get it wrong, so give me a thank woodyah?