KDLJP8935 KDLJP8935
  • 15-05-2018
  • Chemistry
contestada

Calculate the density (in g/l) of ch4(g) at 75 c and 2.1 atm. (r = 0.08206 latm/molk

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Dejanras
Dejanras Dejanras
  • 24-05-2018
Answer is: density of methane is 1.176 g/L.
V(CH
₄) = 1 L.
T = 75°C = 348.15 K.
p = 2.1 atm.
R = 0.08206 L·atm/mol·K.
Ideal gas law: p·V = n·R·T.
n = p·V / R·T.
n
(CH₄) = 2.1 atm · 1 L / 0.08206 L·atm/mol·K · 348.15 K.
n(CH₄) = 0.0735 mol.
m(CH₄) = n(CH₄) · M(CH₄).
m(CH₄) = 0.0735 mol · 16 g/mol.
m(CH₄) = 1.176 g.
d(CH₄) = m(CH₄) ÷ V(CH₄).
d(CH₄) = 1.176 g/L.
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