quianmkm quianmkm
  • 15-05-2018
  • Mathematics
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help!! @mathmate help needed! I need step by step please

help mathmate help needed I need step by step please class=

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LammettHash
LammettHash LammettHash
  • 15-05-2018
Since [tex]\sin^2x+\cos^2x=1[/tex] for all [tex]x[/tex], you can write as a first step

[tex]\dfrac{\cos^2\theta\tan^2\theta}{1-\sin^2\theta}=\dfrac{\cos^2\theta\tan^2\theta}{\cos^2\theta}[/tex]

Then for [tex]\cos\theta\neq0[/tex], you can eliminate both factors of [tex]\cos^2\theta[/tex] in the numerator and denominator to end up with [tex]\tan^2\theta[/tex].
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