tuesdaylane03 tuesdaylane03

15-05-2018
Mathematics

contestada

Solve the system below.

y = x^2 - 4

y= -4

a. 0 , -4
b. -4, 0
c. (0, -4), (-4, 0)
d. there is no real solution

Respuesta :

altavistard altavistard

15-05-2018

To solve this system, let y = x^2 - 4 = -4. Then y = x^2. This is true for all x. There is no single numerical solution. y = x^2 is a function with infinitely many inputs/outputs.

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