thematerialmatrix thematerialmatrix
  • 15-07-2018
  • Mathematics
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Urgent help needed with right triangle trig!

Urgent help needed with right triangle trig class=
Urgent help needed with right triangle trig class=

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MrCoolking MrCoolking
  • 15-07-2018
Let the unknown side's length be 'b' units .

Then by Pythagorean theorem . We have

[tex] {b}^{2} = {c}^{2} - {a}^{2} [/tex]
Now substituting the values of a and c in the above equation we get the value of b.

[tex] {b}^{2} = {24}^{2} - {6}^{2} = 540 \\ \\ b = \sqrt{540} = 6 \sqrt{15} [/tex]
We know that ;

[tex] \tan( \theta) = \frac{b}{a} = \frac{6 \sqrt{15} }{6} = \sqrt{15} [/tex]
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