Seudónimo Seudónimo
  • 12-08-2018
  • Mathematics
contestada

The square root of t is greater than 2 and less than 3.5. How many integer values of t satisfy this condition?

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konrad509
konrad509 konrad509
  • 12-08-2018

[tex] 2<\sqrt t<3.5\\
4<t<12.25\\\\
4<t<12.25 \wedge t\in\mathbb{Z}\\
t\in\{5,6,7,8,9,10,11,12\} [/tex]

8 integers

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bawbdmo
bawbdmo bawbdmo
  • 12-08-2018

We are given that: [tex] 2 < \sqrt{t} < 3.5 [/tex], so if we want to find out what t satisfies this, we have to square all of the compound inequality, giving us:

[tex] 4<t<12.25 [/tex]

So, the integers on this interval are clearly just 5,6,7,8,9,10,11 and 12. That means there are 8 integer values of t that fits the new inequality, so there are 8 roots of t that give us a value between 2 and 3.5

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