oliviacreasongpd3ueq
oliviacreasongpd3ueq oliviacreasongpd3ueq
  • 14-08-2018
  • Mathematics
contestada

(((4^2-(7×2))^4×2)-2)÷3+(5×2)÷2-5

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GoddessofDork
GoddessofDork GoddessofDork
  • 14-08-2018

So for eyes' sake, I will be using different brackets to read the equation better. Here's how to solve this expression:

[tex] (\{[4^2-(7*2)]^4*2\}-2)\div 3+(5*2)\div 2-5\\ (\{[16-14]^4*2\}-2)\div 3+10\div 2-5\\ (\{2^4*2\}-2)\div 3+5-5\\ (\{16*2\}-2)\div 3+5-5\\ (32-2)\div 3+5-5\\ 30\div 3+5-5\\ 10+5-5\\ 10 [/tex]

The answer is 10.

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