To answer this question, we can use the following equation:
[tex] e=\frac{h*c}{lambda} [/tex]
where e is the energy change, h is Planck's constant, c is the speed of light (m/s), and lambda is wavelength in meters. So then we can plug in the information:
[tex] e=\frac{(6.626x10^{-34}J*s)(2.998x10^{8}\frac{m}{s})}{1.08m} [/tex]
[tex] e=\frac{1.9865x10^{-25}J}{1.08} [/tex]
[tex] e=1.84x10^{-25}J [/tex]
So the energy that is omitted by the atom is [tex] 1.84x10^{-25}J [/tex].
