Respuesta :

[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{9\times 9}{81}\\ h=10 \end{cases}\implies V=\cfrac{1}{3}(81)(10)\implies V=270[/tex]