Respuesta :

gmany

The point-slope form of line:

[tex]y-y_1=m(x-x_2)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points (-2, 1) and (1, 2). Substitute:

[tex]m=\dfrac{2-1}{1-(-2)}=\dfrac{1}{3}\\\\y-1=\dfrac{1}{3}(x-(-2))\\\\\boxed{y-1=\dfrac{1}{3}(x+2)}[/tex]

Otras preguntas