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12-12-2018
Mathematics

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Factor 9abc+3ac+12bc completely

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31-01-2019

Answer:

[tex]3c(3(b+1)a+4b)[/tex]

Step-by-step explanation:

The given equation is:

[tex]9abc+3ac+12bc[/tex]

Taking 3c common from all the above terms, we get

⇒[tex]3c(3ab+a+4b)[/tex]

⇒[tex]3c(3(b+1)a+4b)[/tex]

which is the required factorised form.

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