Answer:
11. [tex] p = 59.2^\circ [/tex]
12. C. [tex] x \tan q [/tex]
Step-by-step explanation:
11.
First, find side DB.
(DB)^2 = 6^2 + 5^2
[tex] DB = \sqrt{61} [/tex]
Now find m<p.
[tex] \cos p = \dfrac{adj}{hyp} [/tex]
[tex] \cos p = \dfrac{4}{\sqrt{61}} [/tex]
[tex] p = \cos^{-1} \dfrac{4}{\sqrt{61}} [/tex]
12.
Let the height be y.
[tex] \tan q = \dfrac{y}{x} [/tex]
[tex] y = x \tan q [/tex]
