Given data
mass (m) = 185 g = 0.185 Kg ,
temperature (T₁) = 200°C = 200 + 273 = 473 K
temperature (T₂) = 10°C = 10+273 = 283 K
Specific haet at constant pressure (Cp) = 2.108 Kj/Kg k
Heat transfer (Q) = m.Cp.( T₂- T₁) J
= 0.185 × 2.108 × (283 - 473)
Q = -74.09 KJ
Heat rejected from ice is 74 J
