mastershadow2018
mastershadow2018 mastershadow2018
  • 16-01-2019
  • Mathematics
contestada

what is an equation of the line perpendicular to y=-x-2 and through (-2,4)

Respuesta :

gmany
gmany gmany
  • 17-01-2019

Let [tex]k:y=m_1x+b_1[/tex] and [tex]l:y=m_2x+b_2[/tex]

[tex]l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}[/tex]

We have

[tex]y=-x-2\to m_1=-1[/tex]

Therefore

[tex]m_2=-\dfrac{1}{-1}=1[/tex]

We have the equation of a line:

[tex]y=-1x+b\to y=-x+b[/tex]

Put the coordinates of the point (-2, 4) to the equation of a line:

[tex]4=-(-2)+b[/tex]

[tex]4=2+b[/tex]          subtract 2 from both sides

[tex]2=b\to b=2[/tex]

Answer: y = -x + 2

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