Answer:
∠ADB=35°
Step-by-step explanation:
Given arc AB = 70°.
we have to find the angle ∠ADB
Here, Angle subtended by arc AB at O is ∠AOB = 70°
By the theorem,
The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
∴ ∠AOB=2(∠ADB)
⇒ [tex]\angle ADB=\frac{1}{2}\angle AOB=\frac{1}{2}70^{\circ}= 35^{\circ}[/tex]
hence, angle subtended at the circumference is 35°
