Answer:
[tex](2n-3)(n^2-2n+5)[/tex] = [tex]2n^3-7n^2+16n-15[/tex].
Step-by-step explanation:
We are given the product, [tex](2n-3)(n^2-2n+5)[/tex].
On simplifying the product, we get,
[tex](2n-3)(n^2-2n+5)[/tex]
⇒ [tex]2n^3-4n^2+10n-3n^2+6n-15[/tex]
⇒ [tex]2n^3-7n^2+16n-15[/tex]
Thus, the product of the two polynomials [tex](2n-3)[/tex] and [tex](n^2-2n+5)[/tex] is given by,
[tex](2n-3)(n^2-2n+5)[/tex] = [tex]2n^3-7n^2+16n-15[/tex].
