markarianlaura1 markarianlaura1

16-02-2019
Mathematics

contestada

Find three consecutive odd integers such that the square of the second decreased by four times the first is seven more than six times the third.

please help

Respuesta :

mathecoach mathecoach

16-02-2019

Answer:

x, x+2, x+4

(x+2)^2 - 4(x) = 6(x + 4) + 7

x^2 + 4x + 4 - 4x = 6x + 24 + 7

x^2 - 6x - 27 = 0

x = 9 (∨ x = -3)

The three numbers are

9, 11, 13

but it could be also

-3, -1, 1

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