gemsgianni32ozyp55
gemsgianni32ozyp55 gemsgianni32ozyp55
  • 12-03-2019
  • Mathematics
contestada

Find the product:

(r+2)(r-5)(r-2)(r+5)

Please show all steps.

15 points.

Respuesta :

MrBillDoesMath MrBillDoesMath
  • 12-03-2019

Hello from MrBillDoesMath!

Answer:

r^4- 29r^2 + 100

Discussion:

Rearrange the terms in the product as follows:

(r+2)(r-2) *  (r-5)(r+5)  =

(r^2 - 4) * (r^2-25) =

f^4 - (25+4)r^2 + 4*25 =

r^4- 29r^2 + 100

Thank you,

MrB

Answer Link
maggiesmama1 maggiesmama1
  • 12-03-2019

by rearranging and foiling them

(r+2)(r-2)(r+5)(r-5)

[tex] {r }^{2} - 4[/tex]

[tex] {r}^{2} - 25[/tex]

now foil them

r^4-25r^2-4r^2+100

r^4-29r^2+100

Answer Link

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