Answer
option D)
2.4 seconds
Explanation
Given in the question,
mass of car = 1200kg
speed of car = 19m/s
Force due to direction of travel
F = ma
 = 12000(a)
Force to due frictional force in reverse direction
-F = mg(friction coefficient)
  = -12000(9.81)(0.8)
-mg(friction coefficient) = ma Â
(cancelling mass from both side of equation)
g(0.8) = a
(9.81)(0.8) = a
a = 7.848 m/s²
Use Newton Law of motion
vf - vo = a • t
where vf = final velocity
     vo = initial velocity
     a = acceleration
      t = time
0 - 19 = 7.8(t)
t = 19/7.8
 = 2.436 s
 ≈ 2.4s
