chloekeefer18 chloekeefer18
  • 12-03-2019
  • Mathematics
contestada

Which of the following shows the equation below rewritten in the form ax^2+bx+c=0 ?
(3x)^2=8(x-1)

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Аноним Аноним
  • 13-03-2019

If you square the left hand side, you get

[tex] (3x)^2 = 3^2x^2 = 9x^2 [/tex]

You can expand the right hand side by multiplying both terms by 8:

[tex] 8(x-1) = 8x-8 [/tex]

So, the equation becomes

[tex] 9x^2=8x-8 [/tex]

Subtract the right hand side to move it to the left

[tex]9x^2-8x+8 = 0[/tex]

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