Respuesta :
Answer: [tex]a=\sqrt{c^2-4}[/tex]
Step-by-step explanation:
You know that the Pythagorean Theorem is:
[tex]a^2+b^2=c^2[/tex]
Where "a" and "b" are the legs and "c" is the hypotenuse.
Then, since you need to find Ā the length of side "a" in terms of the hypotenuse "c", you need to solve for "a":
Subtract b² from both sides of the equation:
[tex]a^2+b^2-b^2=c^2-b^2[/tex]
[tex]a^2=c^2-b^2[/tex]
And finally, you need to apply square root to both sides of the equation:
[tex]\sqrt{a^2}=\sqrt{c^2-b^2}\\\\a=\sqrt{c^2-b^2}[/tex]
Then:
[tex]a=\sqrt{c^2-2^2}\\\\a=\sqrt{c^2-4}[/tex]
Ā
Answer:
Final answer is [tex]a=\sqrt{c^2-4}[/tex].
Step-by-step explanation:
Given that b=2. Now using Pythagorean theorem, we need to find the value of a in terms of c.
So let's plug b=2 into formula :
[tex]a^2+b^2=c^2[/tex]
[tex]a^2+2^2=c^2[/tex]
[tex]a^2+4=c^2[/tex]
[tex]a^2=c^2-4[/tex]
Take square root of both sides and use principle root as side length can't be negative.
[tex]a=\sqrt{c^2-4}[/tex]
Hence final answer is [tex]a=\sqrt{c^2-4}[/tex].