Answer:
[tex]\large\boxed{(7x+5)(2x^3-4x^2+9x-3)=14x^4-18x^3+43x^2+24x-15}[/tex]
Step-by-step explanation:
Use FOIL: (a + b)(c + d) = ac + ad + bc + bd
[tex](7x+5)(2x^3-4x^2+9x-3)\\\\=(7x)(2x^3)+(7x)(-4x^2)+(7x)(9x)+(7x)(-3)\\+(5)(2x^3)+(5)(-4x^2)+(5)(9x)+(5)(-3)\\\\=14x^4-28x^3+63x^2-21x+10x^3-20x^2+45x-15\\\\\text{combine like terms}\\\\=14x^4+(-28x^3+10x^3)+(63x^2-20x^2)+(-21x+45x)-15\\\\=14x^4-18x^3+43x^2+24x-15[/tex]
