nyjathompson
nyjathompson nyjathompson
  • 13-06-2019
  • Mathematics
contestada

The circle below is centered at the point (3,1) and has a radius length of 2.What is its equation

The circle below is centered at the point 31 and has a radius length of 2What is its equation class=

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 23-06-2019

Answer:

C. [tex](x-3)^2+(y-1)^2=2^2[/tex]

Step-by-step explanation:

The standard equation of a circle, given the radius r units and center (h,k) is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

From the question, we have the center of the circle to be (3,1) and the radius is 2 units.

We substitute the center and radius of the circle into the equation to get:

[tex](x-3)^2+(y-1)^2=2^2[/tex]

The correct answer is C

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