Answer:
241.27 N
Explanation:
Both the negative charge will pull the positive charge towards it . Let the forces be F₁ and F₂
F₁ = [tex]\frac{9\times10^9\times8\times6.7\times10^{-18}}{(2.3\times10^{-2})^2}[/tex]
F₁ = 91.19 X 10⁻⁵ N
F₂=[tex]\frac{9\times10^9\times8\times13.4\times10^{-18}}{(2.3\times10^{-2})^2}[/tex]
F₂ = 182.38 X 10⁻⁵ N
F₁ and F₂ act at 60 degree so their resultant will be calculated as follows
R² = (91.19)² +(182.38)² + 2 X 91.19 X 182.38 Cos 60
R² = 58209.30
R = 241.27 N
