Powers distribute over multiplications:
[tex](ab)^c = a^c\cdot b^c[/tex]
So, you have
[tex](3k^5)^2 = 3^2 \cdot (k^5)^2[/tex]
Now, [tex]3^2[/tex] is simply 9.
As for [tex](k^5)^2[/tex], we have to use the rule
[tex](a^b)^c = a^{bc}[/tex]
to get
[tex](k^5)^2=k^{5\cdot 2}=k^{10}[/tex]
So, the final answer is
[tex](3k^5)^2 =9k^{10}[/tex]
