whiteblaine5321 whiteblaine5321
  • 13-09-2019
  • Mathematics
contestada

There are 18,017 AIDS deaths in 2003, or 34.5% of the 1995 AIDS deaths. Determine the number of AIDS deaths in 1995.

Respuesta :

windyyork windyyork
  • 17-09-2019

Answer: There are 52223.18 AIDS death in 1995.

Step-by-step explanation:

Since we have given that

Number of AIDS deaths in 2003 = 18,017

Percentage of deaths of 1995 AIDS deaths =34.5%

Let the number of AIDS deaths in 1995 be 'x'.

According to question, it becomes ,

[tex]\dfrac{34.5}{100}\times x=18017\\\\x=18017\times \dfrac{100}{34.5}\\\\x=52223.18[/tex]

Hence, there are 52223.18 AIDS death in 1995.

Answer Link

Otras preguntas

Which formula stands for boric acid?
how do you times 6×6 i there different ways
Why Were Bays Important To The Early Settlement?
An empty bucket is placed under a faucet dripping at a constant rate of 44 milliliters per minute. With the given information, which of these statements is a re
What is the definition of a cell?
how much electricity do we use
Generalize the difference between a succession stage and a climax community
6(n-8) greater than or equal to -18
Which is not a characteristic of a multiparty system? a. There are many major and minor parties. b. Voters have a wide choice of candidates. c. Parties form coa
Of the 95 people enrolled in mathematics class, 93% are present. How many are present?