Answer:
The number of presentation groups of 3 students that can be selected from a group of 5 students equals 10.
Explanation:
The number of different presenters equals the no of possible combinations of 3 students from a pool of 5 students.
Thus the number of possible combinations equals
[tex]\binom{5}{3}=\frac{5!}{(5-3)!\times 3!}=10[/tex]
