Answer:
0.014 in
Explanation:
The Young's module of steel is of E = 210 GPa = 30*10^6 psi
The section of the bolt would be:
A = π/4 * D^2
The stiffness would be:
k = E * A / L
k = π * D^2 * E / (4 * L)
k = π * 0.25^2 * 30*10^6 / (4 * 10) = 147000 lb / in
If I apply a force of 2000 lb, I calculate the stretching with Hooke's law:
Δx = f / k
Δx = 2000 / 147000 = 0.014 in
