Answer:
[tex] \frac{3 \frac{9}{16}}{2x - 1} [/tex]
Step-by-step explanation:
Use Polynomial Long Division to get this:
[tex] \frac{x^{3}}{2} + \frac{ {x}^{2} }{4} + \frac{x}{8} - 1 \frac{7}{16} + \frac{3 \frac{9}{16}}{2x - 1} [/tex]
The remainder is the quantity being set over the divisor, which is 2x - 1.
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