Answer:
The specific heat of ice is 2 j/g. °C
Explanation:
Given data:
Amount of heat = 200 J
Mass of ice = 10 g
Temperature change= 10 °C
Specific heat = ?
Solution:
Formula:
Q = m. c. ΔT
Q = amount of heat
m = mass
c = specific heat
ΔT = change in temperature
Now we will put the values in formula,
Q = m. c. ΔT
200 j = 10 g. c . 10 °C
c = 200 j / 100 g. °C
c = 2 j/ g. °C
The specific heat of ice is 2 j/g. °C.
