Answer:
[tex]E(1) = 1.44\times 10^{-4} v/m[/tex]
[tex]E(2) = 1.34\times 10^{-4} v/m[/tex]
Explanation:
Given data:
diameter of solenoid is 11.1 cm
B = 42.9 mT
dR = 6.65 mT/s
d(1) = 4.34 cm
d(2) = 7.46 cm
we know that
electric field due to solenoid is given as
E = 1/2 dB/dt (r)
[tex]E(1)= \frac{0.0434}{2} \times (6.65\times 10^{-3})[/tex]
[tex]E(1) = 1.44\times 10^{-4} v/m[/tex]
E = 1/2 dB/dt (R^2)/r
[tex]E(2)= \frac{0.055^2}{2\times 0.0746} \times (6.65\times 10^{-3})[/tex]
[tex]E(2) = 1.34\times 10^{-4} v/m[/tex]
