Answer:
k = 11
Step-by-step explanation:
let the points be A(-2,5), B(2,8), C(6,K).
for the points to be collinear slope of line AB maust be equal to line BC.
slope of line AB = [tex]\frac{8-5}{2+2}=\frac{3}{4}[/tex]
slope of line BC = [tex]\frac{k-8}{6-2}=\frac{k-8}{4}[/tex]
therefore [tex]\frac{k-8}{4}= \frac{3}{4}[/tex]
therefore k = 8 + 3
k = 11
