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  • 14-12-2019
  • Physics
contestada

A 175-kg motorcycle goes around an unbanked turn of radius 75.4 m at a steady 112 km/h. Determine its acceleration?

Answer

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cryssatemp
cryssatemp cryssatemp
  • 26-12-2019

Answer: [tex]12.83 m/s^{2}[/tex]

Explanation:

In this case we are talking about the centripetal acceleration [tex]a_{c}[/tex], which can be calculated by:

[tex]a_{c}=\frac{V^{2}}{r}[/tex]

Where:

[tex]V=112 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}=31.11 m/s[/tex] is the speed of the motorcycle

[tex]r=75.4 m[/tex] is the radius of the path the motorcycle is going around

Solving:

[tex]a_{c}=\frac{(31.11 m.s)^{2}}{75.4 m}[/tex]

Finally:

[tex]a_{c}=12.83 m/s^{2}[/tex]

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