hanesandielo7rieStr
hanesandielo7rieStr hanesandielo7rieStr
  • 14-06-2016
  • Mathematics
contestada

Find an equation of the tangent line to the curve at the given point. y=secx (pi/3,2)

Respuesta :

hartnn
hartnn hartnn
  • 14-06-2016
To get the equation of tangent, we need a point on it and its slope.

we already have (x1,y1) = (pi/3,2) on the tangent line.

To get the slope of tangent,
m = derivative of y at the given point.

y = sec x
y' = sec x tan x
at x = pi/3,
y' = sec pi/3 tan pi/3
y'= 2 [tex] \sqrt 3 [/tex]

so the slope of tangent is 2 [tex] \sqrt 3 [/tex]

equation will be
y -y1 = m (x-x1)
y - 2 = 2 [tex] \sqrt 3 [/tex] (x- pi/3)

Thats your equation of tangent.
you can simplify if you want.


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