Answer:
Step-by-step explanation:
[tex]\dfrac{\sqrt{5}-1}{\sqrt{5}+1}=\dfrac{(\sqrt{5}-1)(\sqrt{5}-1)}{(\sqrt{5}+1)(\sqrt{5}-1)}\\\\=\dfrac{5-2\sqrt{5}+1}{5-1}=\dfrac{6-2\sqrt{5}}{4}\\\\=\dfrac{3}{2}-\dfrac{1}{2}\sqrt{5}[/tex]
Comparing this to the form a+b√5, we see that ...
a = 3/2
b = -1/2
