xcoder8082 xcoder8082

14-01-2020
Mathematics

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Find the average value of f(x) = √x+1 over the interval [0, 8].

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LammettHash LammettHash

14-01-2020

The average value of [tex]f(x)[/tex] over [0, 8] is

[tex]\displaystyle\frac1{8-0}\int_0^8\sqrt{x+1}\,\mathrm dx=\frac1{12}(x+1)^{3/2}\bigg|_0^8=\frac{13}6[/tex]

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