Answer:
It diverges.
Step-by-step explanation:
We are given the integral: [tex]\int\limits^\infty_{27} \frac{2}{\sqrt x} dx[/tex]
[tex]\int\limits^\infty_{27} \frac{2}{\sqrt x} dx= \lim_{t \to \infty} \int\limits^t_{27} \frac{2}{\sqrt x} dx=\lim_{t \to \infty} 4\sqrt x|^t_{27}=\infty-12\sqrt3=\infty[/tex]
So, it is divergent.
