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A bullet with a mass of 3.0 gram, moving at speed of 300 m/s, hits and embeds itself in the trunk of a tree. The tree exerts an average force of 250 N on the bullet. What is the distance the bullet travels inside the trunk?

Respuesta :

Distance the bullet travels inside the trunk is 0.54 m Ā 

Explanation:

We have equation for force

Ā  Ā  Ā  Ā  Ā  Force = Mass x Acceleration

Ā  Ā  Ā  Ā  Ā  Force = 250 N

Ā  Ā  Ā  Ā  Ā Mass = 3 g = 3 x 10ā»Ā³ kg Ā 

Ā  Ā  Ā  Ā  Ā 250 = 3 x 10ā»Ā³ x Acceleration

Ā  Ā  Ā  Ā  Ā Acceleration = 83333.33 m/sĀ²

Deceleration of bullet is 83333.33 m/sĀ².

We have equation of motion vĀ² = uĀ² + 2as

Initial velocity, u = 300 m/s Ā 

Acceleration, a = -83333.33 m/sĀ² Ā 

Final velocity, v = 0 m/s Ā 

Substituting Ā 

vĀ² = uĀ² + 2as

0Ā² = 300Ā² + 2 x -83333.33 x s

s = 0.54 m Ā 

Distance the bullet travels inside the trunk is 0.54 m Ā