paigecbrumley paigecbrumley
  • 11-02-2020
  • Mathematics
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does 2 (x-1) + 6x=5(6x-1)+3 have infinite solutions

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scollier160715
scollier160715 scollier160715
  • 11-02-2020

Short Answer.... No

Step-by-step explanation:

2(x−1)+6x=5(6x−1)+3

Step 1: Simplify both sides

2(x−1)+6x=5(6x−1)+3

(2)(x)+(2)(−1)+6x=(5)(6x)+(5)(−1)+3 Distribute

2x+−2+6x=30x+−5+3

(2x+6x)+(−2)=(30x)+(−5+3) Combine Like Terms

8x+−2=30x+−2

8x−2=30x−2

Step 2: Subtract 30x from both sides.

8x−2−30x=30x−2−30x

−22x−2=−2

Step 3: Add 2 to both sides

−22x−2+2=−2+2

−22x=0

Step 4: Divide both sides by -22.

−22x    0

____ =__

−22      -22

x=0

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