Answer:
x < - [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Given
[tex]\frac{1}{2}[/tex] x + [tex]\frac{1}{4}[/tex] > [tex]\frac{3}{2}[/tex] x + [tex]\frac{3}{4}[/tex]
The lowest common multiple of 2 and 4 is 4
Multiply through by 4 to clear the fractions
2x + 1 > 6x + 3 ( subtract 2x from both sides )
1 > 4x + 3 ( subtract 3 from both sides )
- 2 > 4x ( divide both sides by 4 )
- [tex]\frac{2}{4}[/tex] > x
- [tex]\frac{1}{2}[/tex] > x , thus
x < - [tex]\frac{1}{2}[/tex]
