live4dramaoy0yf9
live4dramaoy0yf9 live4dramaoy0yf9
  • 14-02-2020
  • Mathematics
contestada

Identify the logarithmic form of 4^−2 = 0.0625.

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sqdancefan
sqdancefan sqdancefan
  • 14-02-2020

Answer:

  [tex]\log_4{(0.0625)}=-2[/tex]

Step-by-step explanation:

The logarithmic form of ...

  [tex]\displaystyle b^e=v[/tex]

is ...

  [tex]\log_b{(v)}=e[/tex]

The exponent is the logarithm of the value. The base of the logarithm is the base of the exponential term.

Filling in your numbers, b=4, e=-2, v=0.0625, you have ...

  [tex]\log_4{(0.0625)}=-2[/tex]

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