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Triangle PQR has coordinates P(-8,3), Q(-8,6), R(-3,6). If the triangle is translated by using the rule (x,y) (x+4, y-6) what are the coordinates of triangle P'Q'R'?

Respuesta :

Answer:

P' = (-4,-3)

Q' =  (-4,0)

R'= (1,0)

Step-by-step explanation:

The transformation increases the value of the xth-coordinate of each vertex by 4 and decreases the value of the yth-coordinate by 6. We just need to compute this operations in each vertex P Q and R of the triangle. Therefore we have that

P' = (-8+4,3-6) = (-4,-3)

Q' = (-8+4,6-6) = (-4,0)

R`= (-3+4,6-6) = (1,0)

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D)  P' (-4, -3), Q' (- 4, 0), R' (1, 0)

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