Step-by-step explanation:
[tex]x - 6 = 6 \\ \\ \therefore \: x = 6 + 6 \\ \\ \therefore \: x = 12 \\ \\ y - 1 = 0\\ \\ \therefore \: y = 0 + 1 \\ \\ \therefore \: y= 1 \\ [/tex]
Thus the coordinates of P' are (12, 1)
