Respuesta :

claudiagspaulding
so r1/4 = 13.5/r2 = r2/r1 

r1*r2 = 54 ----------eqn(1) 

r2^2 = 13.5r1--------eqn(2) 

from(2) r1 = r2^2/13.5 

substituting this in eqn(1) 

r2^3/13.5 = 54 

r2^3 = 54*13.5 = 729 

r2 = 9 

r1 = 81/13.5 = 6 

so two geometric means between 4, 13.5 are 6 and 9
pedrolok
 two geometric means between 4, 13.5 are 6 and 9

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