14-04-2020
Mathematics

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In the question y= 4(x-2)^2 + 1, what is the vertex?order pair form

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14-04-2020

Vertex is [tex](p,q)[/tex] and our parabola has vertex form of [tex]y=a(x-p)^2+q=4(x-2)^2+1[/tex] that means the vertex is at [tex](2,1)[/tex].

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