Respuesta :

JoshEast
M₁V₁ = M₂V₂ (where M₁ & V₁ are the starting molarity and volume and M₂                               & V₂ are the molarity and volume after dilution)

Substitute known values into the equation and use letters to represent unknown
(0.5M) (250ml) = (x) (840ml)

since 1 ml = 1cm³ then
(0.5M) (250cm³) = (x) (840cm³)

transpose and solve for x

[tex]x = \frac{(0.5M)(250cm^{3}) }{(840cm^{3})} [/tex]

[tex] x = \frac{(125 M)cm^{3} }{(840cm^{3})} [/tex]
        
∴  molarity when diluted to 840 ml  =  0.149 M

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